Mr. Gerson,For #13 the problem is x^2+4 and when I check in the back of the book, it says not factorable. But wouldn't the factorization for this problem be....(x+2)(x+2) or (x+2)^2What am I doing wrong??~Micaela TomPeriod 1
Micaela, x^2+4 is not a square of a binomial. x^2-4 is, but notx^2+4.so, it is not factorable.p.s. (x+2)(x+2) is x^2+4x+4.....hope this helps
Micaela,Number 13 did not have a common factor and it was not a difference of two squares. Saloni B.Period 1
The second comment was a great explanation. I posted it even though nobody took credit. Who should get credit?
oh sorry Mr.Gerson..i accidentally didnt put my name.Hyun p. per.6
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5 comments:
Mr. Gerson,
For #13 the problem is x^2+4 and when I check in the back of the book, it says not factorable. But wouldn't the factorization for this problem be....
(x+2)(x+2) or (x+2)^2
What am I doing wrong??
~Micaela Tom
Period 1
Micaela, x^2+4 is not a square of a binomial. x^2-4 is, but notx^2+4.so, it is not factorable.
p.s. (x+2)(x+2) is x^2+4x+4.....
hope this helps
Micaela,
Number 13 did not have a common factor and it was not a difference of two squares.
Saloni B.
Period 1
The second comment was a great explanation. I posted it even though nobody took credit. Who should get credit?
oh sorry Mr.Gerson..i accidentally didnt put my name.
Hyun p. per.6
Post a Comment