11/3 journal entry Today we learned 3 different patterns, 2 common made errors, and how to multiply trinomials. p1) positive perfect square trinomial (a+b)(a+b)=a2+2ab=b2 p2) negative perfect square trinomial (a+b)(a+b)=a2-2ab-b2 p3) perfect square binomial (a+b)(a-b)=a2-b2 ce1)(x+7)(x-7)=x2+7x-7x-49=x2-14x-49 ce2)(x-7)2=x2-72=x2-49 trinomial)(3x2-2x+4)(x2+5x+1) =3x4+13x3-3x2+18x+4 *note*exponent numbers are all big
11/4 journal entry Today we learned how to multiply a binomial to a binomial and a trinomial to a trinomial. There are two techniques for multiplying binomials (Bob style or Box style). We also spent some time arguing on this problem (x+7)(x-7), but eventually we got it and the answer was x2-49. Otherwise, that is all we mainly did in class.
Today in class we continued learning about Products of Polynomials. Then Mr. Gerson put two binomials with false solutions on the board to see if we were sharp enough to catch the errors. We also worked on multiplying binomials by binomials and trinomials by trinomials. We used the Bob method and Box method to work out all the problems.
Today we learned about different types of patterns that can occur when you multiply binomials. The first pattern is a binomial squared is a perfect square trinomial ex.(a+b)(a+b)=a2+2ab+b2 The second pattern we learned was when two binomials are multipied and the second binomial's second term is negative and they consist of the same numbers you get a perfect square binomial ex.(a+b)(a-b)=a2+b2 We also learned how to multiply trinomials ex.(2x2+3x-4)(2x2-x+3)=4x4+4x3 -5x2+13x-12 (Exponent numbers are big)
11-4-10 Journal Entry, Today we learned about common mistakes we make when we multiply two binomials. Also we learned three patterns. 1st pattern-(a+b)(a-b) 2nd pattern-(a+b)2 3rd pattern-(a-b)2 Then we learned how to multiply trinomials, and we figured out that the "Bob" method doesn't work with trinomials, the best method to use is the box method. Example of a trinomial problem-(3a2-2a+4)(a2+5a+1)
Today we learned about patterns that happen when multiplying binomials. The three are; positive perfect square trinomial, negative perfect square trinomial, and the difference of two perfect squares. Also, we learned how to apply the AMOM solution to multiplying trinomials. It is basically the same as multiplying binomials, except there are nine squares to fill instead of four. EG. (2a^3-4+7b)(3a+6-3b) 2a^3 -4 7b 3a 6a^4 -12a 21ab
6 12a^3 -24 42b <--AMOM
-3b -6a^3b -12b -21b^2
6a^4-12a+21ab+12a^3-24+42b-6a^3b-12b-21b^2
6a^4-12a+21ab+12a^3-24+30b-6a^3b-21b^2
Note: ^ means the number right after it is an exponent
20 comments:
for those who want to know, the alternate assignment was p. 247 43-51 odd.
11/3 journal entry
Today we learned 3 different patterns, 2 common made errors, and how to multiply trinomials.
p1) positive perfect square trinomial
(a+b)(a+b)=a2+2ab=b2
p2) negative perfect square trinomial
(a+b)(a+b)=a2-2ab-b2
p3) perfect square binomial
(a+b)(a-b)=a2-b2
ce1)(x+7)(x-7)=x2+7x-7x-49=x2-14x-49
ce2)(x-7)2=x2-72=x2-49
trinomial)(3x2-2x+4)(x2+5x+1)
=3x4+13x3-3x2+18x+4
*note*exponent numbers are all big
Journal Entries
Period 2:
Period 3:
Period 4:
Period 5: Yuta K.
Period 6:
11/4 journal entry
Today we learned how to multiply a binomial to a binomial and a trinomial to a trinomial. There are two techniques for multiplying binomials (Bob style or Box style). We also spent some time arguing on this problem (x+7)(x-7), but eventually we got it and the answer was x2-49. Otherwise, that is all we mainly did in class.
and YutaK, today is 11/4
Journal Entries
Period 2:
Period 3: Steven Y.
Period 4:
Period 5: Yuta K.
Period 6:
Wait does that mean Yuta was suppose to write he journal entry yesterday or is it a typo? I think it's a typo...
JOURNAL ENTRY-11/4
Today in class we continued learning about Products of Polynomials. Then Mr. Gerson put two binomials with false solutions on the board to see if we were sharp enough to catch the errors. We also worked on multiplying binomials by binomials and trinomials by trinomials. We used the Bob method and Box method to work out all the problems.
~GISELLE DELA CRUZ
Journal Entries
Period 2: Giselle D.
Period 3: Steven Y.
Period 4:
Period 5: Yuta K.
Period 6:
Today we learned about different types of patterns that can occur when you multiply binomials. The first pattern is a binomial squared is a perfect square trinomial
ex.(a+b)(a+b)=a2+2ab+b2
The second pattern we learned was when two binomials are multipied and the second binomial's second term is negative and they consist of the same numbers you get a perfect square binomial
ex.(a+b)(a-b)=a2+b2
We also learned how to multiply trinomials
ex.(2x2+3x-4)(2x2-x+3)=4x4+4x3
-5x2+13x-12
(Exponent numbers are big)
Journal Entry 11/4
Today, we learned three types of patterns: (a+b)(a+b),(a+b)(a-b), and (a-b)(a-b).
(a+b)(a+b) is called a positive perfect square trinomial and the solution to it is: a(squared)+ 2ab+ b(squared.
(a-b)(a-b)is called a negative perfect square trinomial and the soltuion is: a(squared)-2ab+b(squared)
(a+b)(a-b) is called a perfect square BINOMIAL and the solution is: a(squared)-b(squared)
overall, i leanred to not be careless because that s where we make mistakes the most.
- David Seo, sixrth period
Hi, I was absent today, so is there any notes or work I missed? I can do tonight's assignment, since it is on the blog.
adam there was a whole bunch of notes and if u read the journals u should be able to no wat we did today
Period 2: Giselle D.
Period 3: Steven Y.
Period 4: Kyle O.
Period 5: Yuta K.
Period 6: David S.
11-4-10 Journal Entry,
Today we learned about common mistakes we make when we multiply two binomials. Also we learned three patterns.
1st pattern-(a+b)(a-b)
2nd pattern-(a+b)2
3rd pattern-(a-b)2
Then we learned how to multiply trinomials, and we figured out that the "Bob" method doesn't work with trinomials, the best method to use is the box method.
Example of a trinomial problem-(3a2-2a+4)(a2+5a+1)
Today we learned about patterns that happen when multiplying binomials. The three are; positive perfect square trinomial, negative perfect square trinomial, and the difference of two perfect squares. Also, we learned how to apply the AMOM solution to multiplying trinomials. It is basically the same as multiplying binomials, except there are nine squares to fill instead of four. EG. (2a^3-4+7b)(3a+6-3b)
2a^3 -4 7b
3a 6a^4 -12a 21ab
6 12a^3 -24 42b <--AMOM
-3b -6a^3b -12b -21b^2
6a^4-12a+21ab+12a^3-24+42b-6a^3b-12b-21b^2
6a^4-12a+21ab+12a^3-24+30b-6a^3b-21b^2
Note: ^ means the number right after it is an exponent
Giselle, it's called AMOM.
Period 2: Giselle D.
Period 3: Steven Y. Margaux N.
Period 4: Kyle O. Stuart R.
Period 5: Yuta K.
Period 6: David S.
11-4 Journal entry
In class today we learned about Products of Polynomials. Mr. Gerson tried to trick us by writing two wrong answers on the board.
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